Finding Equivalent Resistance

Okay Don, what ever.

Reply to
Roy Q.T.
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in article snipped-for-privacy@storefull-3256.bay.webtv.net, Roy Q.T. at snipped-for-privacy@webtv.net wrote on 6/3/05 7:50 PM:

In the probably vain hope to see this thread ended, the answer to the resistance between adjacent nodes of an infinite square array of connected resistors, each of resistance R, is R/2. For a triangular array it would be

2R/3. That is the same as for a hexagonal array.

As for all this blah blah about Thevenin's theorem and superposition, it is all a consequence from the overriding concept of resistor network linearity.

Bill

Reply to
Repeating Rifle

-------- Thanks: You are right on. If superposition doesn't hold true, it is because linearity is not present and the usual circuit theorems are so much hogwash. However, superposition is inherently the direct use of of linearity. F(x+y) =F(x)+F(y).

Reply to
Don Kelly

I hate finding equivalent resitance

=AEoy

Reply to
Roy Q.T.

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