Okay Don, what ever.
Finding Equivalent Resistance
Jun 01, 2005
23 Replies
in article snipped-for-privacy@storefull-3256.bay.webtv.net, Roy Q.T. at snipped-for-privacy@webtv.net wrote on 6/3/05 7:50 PM:
In the probably vain hope to see this thread ended, the answer to the resistance between adjacent nodes of an infinite square array of connected resistors, each of resistance R, is R/2. For a triangular array it would be
2R/3. That is the same as for a hexagonal array.As for all this blah blah about Thevenin's theorem and superposition, it is all a consequence from the overriding concept of resistor network linearity.
Bill
-------- Thanks: You are right on. If superposition doesn't hold true, it is because linearity is not present and the usual circuit theorems are so much hogwash. However, superposition is inherently the direct use of of linearity. F(x+y) =F(x)+F(y).
I hate finding equivalent resitance
=AEoy
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