Not really OT givien the recent thread.
Buoyancy gedanken
Take a 3 inch inside-diameter tube, one end is open, the other end is closed with a cap with a rod going through it, and this terminates in a piston that seals watertight to the walls of the cylinder. The purpose of the piston/rod is to form a moveable bottom for the cylinder.
Think of it as a hydraulic cylinder with the piston and shaft still in place, but the other end is cut off.
Let the piston have a valve in it so that water can be drained through to the bottom of the cylinder, and the bottom of the cylinder also has a drain valve.
The system starts with the piston at the bottom of the cylinder, the piston valve is open, the cylinder valve is closed. Whatever cylinder volume exists below the piston is filled with water, and the rod seals watertight to the cap.
Further assume the rod is infinitely thin, so the volume of the rod inside the cylinder does not increase as the piston is pushed up into the cylinder. (Or, just forget the rod, and assume the piston moves up and down the bore via magic, magnetism, etc.)
Water fills the cylinder (held open end up) to within say 1 inch of the top. An item floats on top of the water, not fully submerged. The moveable bottom is, say, one foot from the bottom of the floating object.
Lets make it easy and say the object is cylindrical and is only slighty smaller than the bore of the cylinder.
Keep the piston valve open, keep the cylinder valve closed. Piston moves up, water level does not change since the water above the piston moves to below the piston via the valve.
Bring the piston up to, say, 0.125 inches below the object.
Is the object still flaoting? Has its position in the cylinder changed?
Assume the object fits close enough in the bore, and that the piston is close enough to the object, that the weight of the water above the piston is less than that of the floating object.
Is this even possible?
Close the valve in the piston.
Does the object move?
Drain the water below the piston.
Does the object move?
Dave