Buoyancy gedanken

I wonder if this could be considered as a variation of the "hydrostatic paradox" problem? If you have a 1' diameter pipe and a 1" dia. pipe and they are both vertical and 10' long full of water, a pressure gauge placed at the bottom of either will read the same. In the floating object experiment the pressure on the bottom of the object in PSI is a function of the height of the water from the surface to the bottom of the object rather than the quantity of water. That's how I analyzed the problem anyway. Engineman

Define the system from the reference frame of the floating object.

"Fluid will rise around the object until the pressure due to the column of fluid (column as measured from the bottom of the object to the top of the fluid), times the area of the bottom of the object, equals the weight of the object", assuming the object will float.

Very clean conceptually for flat-bottomed objects, just a little calculus for irregular objects.

Dave

With that definition, yes. I'll defer to you to explain how an object displaced 150 grams of liquid when there were less than 20 grams of liquid to begin with ...

Exactly. That's true both in the constrained case and in a lake or pool.

Well, this has been an interesting thread, I learned a few things about buoyancy and saw an example of military intelligence.

Engineman

On Thu, 07 Jun 2007 12:30:49 -0700, " snipped-for-privacy@aol.com"

Military intel in this thread?

I think that was a poke at me Don...;-)

Pete